Biot-Savart's law and Vector Potential Apr. 18, 2007
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Magnetic flux density
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Biot-Savart's Law (Sect. 5.4):
Given current density or current find
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Magnetic flux (Sect. 5.3)
+
Magnetic vector potentials
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Vector Poisson's equation:
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Applications:
(T);
permeability and
for free space
or
for finite cross section conductor
for surface current
(or
)
for thin wire
Note:
with
and
being
position vector of the observation point and source point.
(Wb)
Maxwell's equation for static field:
is solenoidal
and
(Sect. 5.3):
solenoidal
and by our choice
, called Coulomb's gauge
for finite cross section conductor
for surface current
(or
)
for thin wire
Note:
with
and
being
position vector of the observation point and source point.
Another way to find flux
; direction of
the path follows the direction of
on the surface enclosed
by the path according to right hand rule
Vector potential provides an easier way to find
, i.e.
; particularly for antenna design.
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HW #20 Due 4/24/07
1. Consider a uniform current density
and a non-uniform current density
.
Find the following parameters for
and
: a) the current density at (-3,4,6), b) the rate of increase
in the volume charge density at (1,-2,3), c) the current crossing a disk
of radius 5mm placed on the xy-plane and centered at the origin.
2. Solve problem 5.6 (page 224) with following steps:
a) Draw a diagram of a coaxial cable with an inner conductor with
current flowing into the paper and an outer conductor with current flowing
out of the paper.
b) Identify number of regions in the diagram and find the current enclosed
by a circular path in each region.
c) Apply Ampere's law to find H field
by dividing the current enclosed in each region
with the length of the circular path.
Notice that H should be a piece-wise function of radius
of the circular
path.
d) Find B as a piece-wise function and plot it versus
.
Extra-credit:
A long circular conductor of radius a carriers a current with
,
when placed along the z-axis.
Find
inside and outside the conductor.
(Notice: although
is up to a, the circular path with
will
still enclose current from
.)